An electric current is viewed as flow of positive charges from the positive terminal to the negative terminal. This choice of direction is purely conventional. As on today, we know that electrons are negatively charged and thus, the conventional current flows in the direction opposite to the direction of electron motion. Also, since electrons move from lower …
An 18 Ω, 9 Ω, and 6 Ω resistor are connected in parallel to an emf source. A current of 4 A is the 9 Ω resistor. How do you calculate the resistance of the circuit? What is the potential difference across the source?
current= voltage divided by Resistance. so 9/3=3 current is 3 amperes. A 9-V battery is connected to a light bulb with a resistance of 3 ohm.
The curent is =0.09A Apply Ohm''s Law U=RI The voltage is U=9V The resistance is R=100Omega The current is I=U/R=9/100=0.09A
1 Answer. A magnetic field is a phenomenon that can occur in one of two ways: it is induced by a current carrying wire, or it is generated naturally by the charge arrangement in a ferrous material. That said, voltage is not exactly directly related to a magnetic field. However, because current is a result of a voltage in a circuit, fluctuations ...
The current I is 0.9 A. To apply Kirchoff''s Loop rule we have to go (or imagine going) all the way round the loop (or loops), adding up the net voltage drops along the way. The total of the voltage drops must be zero. (In this approach, we count voltage rises as negative voltage drops.) A quick reminder about the signs of the voltages if you cross a resistor in the …
It also doubles. By Ohm''s Law, V=IR, where V is the voltage, I is the current, and R is the resistance. We can solve for current and replace V with 2V to see the result. =>I=(2V)/R This is equivalent to I=2(V/R). Therefore, we can see that if the voltage doubles, the current also doubles for the same resistance.
A 2.0-ohm resistor is connected in a series with a 20.0 -V battery and a three-branch parallel network with branches whose resistance are 8.0 ohms each. Ignoring the battery''s internal resistance, what is the current in the battery? Show your work.
I = U raw Rext = 9V 9Ω = 1A current. In reality we measure 0.8A. So the internal resistance of the battery in this case: Rint = Rtot −Rext = 11.25Ω − 9Ω = 2.25Ω. You can also work with the voltage loss on the poles of your battery. I''ll leave that to you. A real-life battery can be described as an ideal voltage source with an internal ...
There are chemicals in the battery. The chemical energy is converted into electrical energy and provides the current. A baterry basically consists of electrochemical cells. When a battery is supplying electric power, its positive terminal is the cathode and its negative terminal is the anode. The terminal marked negative is the source of electrons that when …
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